Question

1. how many tons of asphalt concrete will be required to overlay a 2.5 - mile - long, 24 - ft - wide road with 3 in. of wearing course asphalt concrete that has a density of 147.9 pcf?

Explanation:

Step1: Convert units

First, convert all units to feet.

• Length: \(2.5\) miles. Since \(1\) mile \( = 5280\) feet, then \(2.5\times5280=13200\) feet.
• Width: \(24\) feet.
• Thickness: \(3\) inches. Since \(1\) foot \( = 12\) inches, then \(3\div12 = 0.25\) feet.

Step2: Calculate volume

Use the formula \(V=l\times w\times h\) (where \(l\) is length, \(w\) is width, \(h\) is height/thickness).
\(V=13200\times24\times0.25\)

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Step3: Calculate weight in pounds

Use the formula \(m=
ho\times V\) (where \(
ho\) is density and \(V\) is volume). Given \(
ho = 147.9\space pcf\) (pounds per cubic foot)
\(m=147.9\times79200\)

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Step4: Convert pounds to tons

Since \(1\) ton \( = 2000\) pounds.
\(n=\frac{11713680}{2000}=5856.84\) tons

Answer:

\(5856.84\) tons