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d. 15 60. carolyn buys flour for 16 cents per ounce and sugar for 24 ce…

Question

d. 15

  1. carolyn buys flour for 16 cents per ounce and sugar for 24 cents per ounce. how many ounces of flour are in a mixture of flour and sugar that costs 22 cents per ounce and weighs 20 ounces?

a. 4 ounces
b. 5 ounces
c. 6 ounces
d. 7 ounces

  1. giselle made several apple and peach pies. she bought peaches for $4 per pound and apples for $2 per pound. if giselle spent $60 to buy 24 pounds of fruit, how many pounds of peaches did she buy?

a. 6
b. 10
c. 18
d. 20

  1. four years ago mary was twice as old as john. in three years john will be two - thirds as old as mary. how old is mary now?

a. 18
b. 19
c. 12
d. none of these

  1. mary is twice as old as susan now, but 8 years ago she was 4 times as old as susan. how old was susan 4 years ago?

a. 20 years old
b. 12 years old
c. 8 years old
d. 4 years old

Explanation:

Problem 60:

Step1: Define variables

Let \( x \) be ounces of flour, \( y \) be ounces of sugar. We know \( x + y = 20 \) (total ounces) and \( 16x + 24y = 22\times20 \) (total cost).

Step2: Simplify cost equation

\( 16x + 24y = 440 \). Divide by 8: \( 2x + 3y = 55 \).

Step3: Solve system of equations

From \( x + y = 20 \), we get \( x = 20 - y \). Substitute into \( 2x + 3y = 55 \):
\( 2(20 - y) + 3y = 55 \)
\( 40 - 2y + 3y = 55 \)
\( y = 15 \). Then \( x = 20 - 15 = 5 \).

Step1: Define variables

Let \( p \) be pounds of peaches, \( a \) be pounds of apples. We have \( p + a = 24 \) (total pounds) and \( 4p + 2a = 60 \) (total cost).

Step2: Simplify cost equation

Divide \( 4p + 2a = 60 \) by 2: \( 2p + a = 30 \).

Step3: Solve system of equations

From \( p + a = 24 \), \( a = 24 - p \). Substitute into \( 2p + a = 30 \):
\( 2p + 24 - p = 30 \)
\( p = 6 \).

Step1: Define variables

Let Mary’s current age be \( M \), John’s current age be \( J \). Four years ago: \( M - 4 = 2(J - 4) \). In three years: \( J + 3 = \frac{2}{3}(M + 3) \).

Step2: Simplify first equation

\( M - 4 = 2J - 8 \) → \( M = 2J - 4 \).

Step3: Substitute into second equation

\( J + 3 = \frac{2}{3}(2J - 4 + 3) \)
\( J + 3 = \frac{2}{3}(2J - 1) \)
Multiply by 3: \( 3J + 9 = 4J - 2 \)
\( J = 11 \). Then \( M = 2(11) - 4 = 18 \).

Answer:

B. 5 ounces

Problem 61: