Question

1. an acid with a ph of 2.0 has about how many more h+ ions as an acid with a ph of 5.0? (p. 3)

Explanation:

Step1: Recall pH formula

The formula for pH is $pH = -\log_{10}[H^+]$, so $[H^+] = 10^{-pH}$.

Step2: Calculate $[H^+]$ for pH=2

For $pH = 2.0$, $[H^+]_1 = 10^{-2.0}=10^{-2}\ \text{M}$.

Step3: Calculate $[H^+]$ for pH=5

For $pH = 5.0$, $[H^+]_2 = 10^{-5.0}=10^{-5}\ \text{M}$.

Step4: Find the ratio

Divide $[H^+]_1$ by $[H^+]_2$: $\frac{[H^+]_1}{[H^+]_2}=\frac{10^{-2}}{10^{-5}} = 10^{-2 - (-5)}=10^{3}=1000$.

Answer:

1000 times more