Question

13
what are the products of this reaction? * (0.5 points)
__agc₂h₃o₂(aq) + __mgcl₂(aq) →
○ mgc₂h₃o₂ + agcl₂
○ agcl₂ + mg(c₂h₃o₂)₂
○ mgh₃o₂ + agccl₂
○ agcl + mg(c₂h₃o₂)₂

Explanation:

Step1: Identify Reaction Type

This is a double - displacement reaction. In double - displacement reactions, the cations and anions of the two reactants switch places. The general form is \(AB + CD
ightarrow AD+CB\). For the reaction \(AgC_{2}H_{3}O_{2}(aq)+MgCl_{2}(aq)\), the cation of the first reactant is \(Ag^{+}\) and the anion is \(C_{2}H_{3}O_{2}^{-}\); the cation of the second reactant is \(Mg^{2 +}\) and the anion is \(Cl^{-}\).

Step2: Determine Products by Swapping Ions

When we swap the ions, the new combinations are: \(Ag^{+}\) with \(Cl^{-}\) and \(Mg^{2+}\) with \(C_{2}H_{3}O_{2}^{-}\).

• The formula for the compound formed from \(Ag^{+}\) and \(Cl^{-}\): The charge of \(Ag^{+}\) is \( + 1\) and the charge of \(Cl^{-}\) is \(-1\), so the formula is \(AgCl\).
• The formula for the compound formed from \(Mg^{2+}\) and \(C_{2}H_{3}O_{2}^{-}\): The charge of \(Mg^{2+}\) is \(+2\) and the charge of \(C_{2}H_{3}O_{2}^{-}\) is \(- 1\). To balance the charges, we need 2 \(C_{2}H_{3}O_{2}^{-}\) ions for each \(Mg^{2+}\) ion. So the formula is \(Mg(C_{2}H_{3}O_{2})_{2}\).

We also need to check the solubility (though for the purpose of identifying products, the ion - swapping is the main step here). \(AgCl\) is insoluble in water (a precipitate), and \(Mg(C_{2}H_{3}O_{2})_{2}\) is soluble.

Now let's check the options:

• Option 1: \(MgC_{2}H_{3}O_{2}+AgCl_{2}\) is incorrect. The formula for the magnesium acetate should be \(Mg(C_{2}H_{3}O_{2})_{2}\) (because \(Mg^{2+}\) has a \(+2\) charge and \(C_{2}H_{3}O_{2}^{-}\) has a \(- 1\) charge) and \(AgCl_{2}\) is incorrect as \(Ag^{+}\) and \(Cl^{-}\) form \(AgCl\) (1:1 ratio).
• Option 2: \(AgCl_{2}+Mg(C_{2}H_{3}O_{2})_{2}\) is incorrect because \(Ag^{+}\) and \(Cl^{-}\) form \(AgCl\) (not \(AgCl_{2}\)).
• Option 3: \(MgH_{3}O_{2}+AgCCl_{2}\) is incorrect as the ion - swapping is not done correctly.
• Option 4: \(AgCl + Mg(C_{2}H_{3}O_{2})_{2}\) matches the products we determined from the double - displacement reaction.

Answer:

\(AgCl + Mg(C_{2}H_{3}O_{2})_{2}\) (the fourth option: \(AgCl + Mg(C_{2}H_{3}O_{2})_{2}\))