Question

1. the shape of a co₂ molecule is

lewis structure for co₂
: f :
( ddot { o } = c = ddot { o } )
( \begin{array} { l l } { \text { a. linear } } & { \text { c. trigonal planar } } \\ { \text { b. bent } } & { \text { d. tetrahedral } } end{array} )

1. a molecule of bf, has a molecular share of trigonal planar. what is the bond angle of

this molecule?
( \begin{array} { l l } { \text { a. } 180 ^ { circ } } & { \text { c. } 109.5 ^ { circ } } \\ { \text { b. } 120 ^ { circ } } & { \text { d. } 90 ^ { circ } } end{array} )

1. what is the name for the following compound?

( \begin{array} { l } { \text { a. phosphorous tetrabromide } } \\ { \text { b. monophoourus pentabromide } } \\ { \text { c. phosphorus pentabromide } } \\ { \text { d. phosphorus hexabromide } } end{array} )
pbr₅

Explanation:

• Question 13: In the Lewis structure of \(CO_2\), the central carbon atom has two double - bond electron groups and no lone pairs. According to VSEPR (Valence - Shell Electron - Pair Repulsion) theory, the molecular geometry is linear.
• Question 14: For a trigonal planar molecular geometry (e.g., \(BF_3\)), the bond angles are \(120^{\circ}\) because the three electron - group (bonding groups in this case) around the central atom are arranged symmetrically in a plane.
• Question 15: When naming binary covalent compounds, we use prefixes. The formula \(PBr_5\) has one phosphorus (\(P\)) atom (prefix “mono -” is omitted for the first element when there is one) and five bromine (\(Br\)) atoms. The prefix for five is “penta -”, so the name is phosphorus pentabromide.

Answer:

1. A. Linear
2. B. \(120^{\circ}\)
3. C. Phosphorus pentabromide