Question

1. ¿qué elemento se encuentra en el periodo 4 y grupo 6, de la tabla periódica? ______

Explanation:

Step1: Recall Periodic Table Structure

Periods are horizontal rows, groups vertical columns. Period 4 has elements with electron shells \(n = 4\). Group 6 (or 16 in modern numbering? Wait, traditional group numbering: group 6 is VIB, but wait, the question is "grupo 6" – in Spanish, "grupo" for the periodic table: in the old numbering, group 6 (IUPAC 16? No, wait, old IUPAC was 1 - 18, but older European was 1A - 8A, 1B - 8B. Wait, no, the element in period 4, group 6 (old numbering, group 6 is chromium? No, wait, period 4: row 4. Group 6 (old group 6, which is IUPAC group 6: elements like Cr, Mo, W. Wait, period 4, group 6: chromium? No, wait, group 6 (old) is VIB, but wait, the element in period 4, group 6 (modern IUPAC group 16? No, group 16 is oxygen family. Wait, no, the question is "grupo 6" – maybe in the Spanish - language curriculum, group 6 (old numbering, group 6 as in the 1 - 18? No, wait, let's check: period 4 (row 4), group 6 (column 6). The periodic table: period 1: H, He; period 2: Li - Ne; period 3: Na - Ar; period 4: K - Kr. Group 6: in the old (US) numbering, group 6 is VIB, which is Cr, Mo, W... So period 4, group 6: chromium? No, wait, no – wait, group 6 (IUPAC 16? No, IUPAC group 6 is the transition metals, group 16 is chalcogens. Wait, maybe the question is using the old group numbering where group 6 is the 6th column (excluding noble gases). Wait, let's list period 4 elements: K (1), Ca (2), Sc (3), Ti (4), V (5), Cr (6), Mn (7), Fe (8), Co (9), Ni (10), Cu (11), Zn (12), Ga (13), Ge (14), As (15), Se (16), Br (17), Kr (18). Ah! Wait, if "grupo 6" is the 6th group (column) in the 1 - 18 numbering? No, group 6 (IUPAC) is column 6, which is Cr (chromium), but wait, in the 1 - 18 numbering, group 6 is column 6, elements: Cr, Mo, W, Sg. So period 4, group 6: chromium (Cr)? No, wait, no – wait, the element in period 4, group 16 (chalcogens) is selenium (Se). Wait, maybe the question has a translation issue. Wait, "grupo 6" – maybe "grupo 16" was mistyped? No, the user wrote "grupo 6". Wait, no, let's check again. Period 4: row 4. Group 6 (old numbering, group 6 as in the 8 - group system: group 6 is VIB, elements Cr, Mo, W. So period 4, group 6: chromium (Cr)? But wait, no, in the 8 - group system, group 6 is between group 5 and 7. Wait, maybe the question is in the modern IUPAC group numbering, group 16 (chalcogens) – period 4, group 16: selenium (Se). But the question says "grupo 6". There's confusion here. Wait, maybe the Spanish "grupo 6" corresponds to the old - style group numbering where group 6 is the 6th main group (A group), but no, main groups are 1A - 8A, transition are B. Wait, no, let's check the atomic numbers. Period 4: n = 4. The electron configuration for period 4: the outermost shell is n = 4. For group 6 (old group 6, VIB), the electron configuration is \( [Ar] 4s^2 3d^4 \) (Cr) or \( [Ar] 4s^1 3d^5 \) (Cr has a special configuration). Wait, but maybe the question is using the modern IUPAC group numbering where group 6 is column 6, so Cr. But wait, another approach: the periodic table has period 4 (row 4), group 6 (column 6). Let's list the elements in period 4 by group:

Group 1: K

Group 2: Ca

Group 3: Sc

Group 4: Ti

Group 5: V

Group 6: Cr

Group 7: Mn

Group 8: Fe

Group 9: Co

Group 10: Ni

Group 11: Cu

Group 12: Zn

Group 13: Ga

Group 14: Ge

Group 15: As

Group 16: Se

Group 17: Br

Group 18: Kr

Ah! So if "grupo 6" is group 6 (column 6), then the element is Chromium (Cr). But wait, maybe the question meant group 16? No, the question says "grupo 6". Wait, maybe a translation error: "grupo 6" could be "group 16" in some contexts? No, 6 and 16 are different. Wait, let's check the Spanish term: "grupo" in the periodic table is "group". So "periodo 4 y grupo 6" – period 4, group 6. So the element is Chromium (Cr)? But wait, no, in the modern IUPAC, group 6 is column 6, which is Cr, Mo, W, Sg. So period 4, group 6: Chromium (Cr). But wait, another thought: maybe the question is using the "grupo" as the 1 - 8 group system (old), where group 6 is the 6th group (main group), but that would be oxygen family, but oxygen is period 2, sulfur period 3, selenium period 4. Wait, that's group 16. So there's a confusion between group numbering systems. In the old US system, groups were 1A - 8A (main) and 1B - 8B (transition). In the old European system, it was 1 - 8 for main, 9 - 18 for transition? No, that's not right. Wait, the key is: period 4 (n = 4), group 6. Let's check the atomic number. The element in period 4, group 6 (IUPAC group 6) is Chromium (Cr), atomic number 24. But if it's group 16 (chalcogens), it's Selenium (Se), atomic number 34. Which is correct? Let's see the Spanish question: "¿Qué elemento se encuentra en el periodo 4 y grupo 6, de la tabla periódica?" – "Which element is in period 4 and group 6 of the periodic table?"

In the IUPAC group numbering (1 - 18), group 6 is the transition metals, column 6: Cr (period 4), Mo (period 5), W (period 6), Sg (period 7). So period 4, group 6: Chromium (Cr). But maybe the question is using the old - style group numbering where group 6 is the 6th main group (A group), which would be group 16 in IUPAC. That's a common confusion. Let's check the electron configuration. For period 4, the valence shell is n = 4. For group 6 (IUPAC 6), the electron configuration is \( [Ar] 4s^2 3d^4 \) (Cr) or \( [Ar] 4s^1 3d^5 \) (due to half - filled d - orbitals). For group 16 (IUPAC 16), the electron configuration is \( [Ar] 4s^2 4p^4 \) (Se).

Given that in many Spanish - language textbooks, the old group numbering (1A - 8A, 1B - 8B) is still used, where group 6B is the transition group, but the question says "grupo 6" – maybe it's a typo for "grupo 16", but assuming the question is correct as "grupo 6", the element is Chromium (Cr). But wait, let's confirm with the periodic table:

Period 1: 1

Period 2: 2

Period 3: 3

Period 4: 4

Group 1: 1

Group 2: 2

Group 3: 3

Group 4: 4

Group 5: 5

Group 6: 6

So the element in period 4, group 6 is Chromium (Cr). Wait, no, wait: the first period has H, He (period 1). Period 2: Li - Ne (period 2). Period 3: Na - Ar (period 3). Period 4: K - Kr (period 4). So the 6th element in period 4 (counting from K as 1) is Cr (K(1), Ca(2), Sc(3), Ti(4), V(5), Cr(6)). Yes, so that's correct.

Step2: Confirm the Element

By looking at the periodic table, period 4 (row 4) and group 6 (column 6) corresponds to the element Chromium (Cr). Wait, but wait, another way: the atomic number. The element in period 4, group 6: the electron configuration is \( [Ar] 4s^1 3d^5 \) (Cr) or \( [Ar] 4s^2 3d^4 \) (theoretical, but Cr has the first configuration due to stability of half - filled d - orbitals). The atomic number is 24.

Answer:

Chromium (Cr) (or in Spanish: Cromio (Cr))