Question

02 question (4 points)
how many atoms of iron are there in 2.01 moles of each of the following?
1st attempt
part 1 (1 point)
wolframite, fewo₄ atoms fe
part 2 (1 point)
pyrite, fes₂ atoms fe
part 3 (1 point)
magnetite, fe₃o₄ atoms fe
part 4 (1 point)
hematite, fe₂o₃ atoms fe

Explanation:

Part 1: For \(FeWO_4\)

Step1: Determine moles of Fe

In \(FeWO_4\), there is 1 mole of Fe per mole of \(FeWO_4\). So moles of Fe = 2.01 mol.

Step2: Calculate number of atoms

Using Avogadro's number \(N = n\times N_A\), where \(n = 2.01\) mol and \(N_A=6.022\times 10^{23}\) atoms/mol.
\(N=2.01\times6.022\times 10^{23}=1.21\times 10^{24}\) atoms.

Part 2: For \(FeS_2\)

Step1: Determine moles of Fe

In \(FeS_2\), there is 1 mole of Fe per mole of \(FeS_2\). So moles of Fe = 2.01 mol.

Step2: Calculate number of atoms

Using \(N = n\times N_A\), with \(n = 2.01\) mol and \(N_A = 6.022\times 10^{23}\) atoms/mol.
\(N=2.01\times6.022\times 10^{23}=1.21\times 10^{24}\) atoms.

Part 3: For \(Fe_3O_4\)

Step1: Determine moles of Fe

In \(Fe_3O_4\), there are 3 moles of Fe per mole of \(Fe_3O_4\). So moles of Fe \(=2.01\times3 = 6.03\) mol.

Step2: Calculate number of atoms

Using \(N=n\times N_A\), with \(n = 6.03\) mol and \(N_A=6.022\times 10^{23}\) atoms/mol.
\(N = 6.03\times6.022\times 10^{23}=3.63\times 10^{24}\) atoms.

Part 4: For \(Fe_2O_3\)

Step1: Determine moles of Fe

In \(Fe_2O_3\), there are 2 moles of Fe per mole of \(Fe_2O_3\). So moles of Fe \(=2.01\times 2=4.02\) mol.

Step2: Calculate number of atoms

Using \(N=n\times N_A\), with \(n = 4.02\) mol and \(N_A=6.022\times 10^{23}\) atoms/mol.
\(N=4.02\times6.022\times 10^{23}=2.42\times 10^{24}\) atoms.

Answer:

• Part 1: \(1.21\times 10^{24}\) atoms Fe
• Part 2: \(1.21\times 10^{24}\) atoms Fe
• Part 3: \(3.63\times 10^{24}\) atoms Fe
• Part 4: \(2.42\times 10^{24}\) atoms Fe