Question

you can spend at most $3.75 at a market. apples cost $0.40 each, and pears cost $0.60 each. let x be numbers of apples and y be numbers of pears. write an inequality that represents the numbers of apples and pears you can buy. an inequality is \square. is (3, 2) a solution of the inequality? \bigcirc yes \bigcirc no

Explanation:

Step1: Write the inequality

Let \( x \) be the number of apples and \( y \) be the number of pears. Apples cost \$0.40 each, so the cost of apples is LXI2. Pears cost \$0.60 each, so the cost of pears is \( 0.60y \). The total cost must be at most \$3.75, so the inequality is \( 0.40x + 0.60y \leq 3.75 \).

Step2: Check if (3, 2) is a solution

Substitute \( x = 3 \) and \( y = 2 \) into the left - hand side of the inequality:
\( 0.40(3)+0.60(2)=1.2 + 1.2=2.4 \)
Since \( 2.4\leq3.75 \), the point (3, 2) satisfies the inequality.

Answer:

yes