Question

word problem involving the probability of a union
in a big cooler in the kitchen there are the following drinks: 5 bottles of soda, 12 bottles of juice, and 6 cans of juice. but, there are no cans of soda. jina just came in from playing outside and is going to choose one of these drinks at random from the cooler. what is the probability that the drink jina chooses is in a can or is a soda?
do not round intermediate computations, and round your answer to the nearest hundredth.
(if necessary, consult a list of formulas.)

Explanation:

Step1: Calculate total number of drinks

Total drinks = \(5 + 12+6=23\)

Step2: Calculate number of drinks that are in a can or a soda

Number of cans of juice \(= 6\), number of sodas \(=5\). Since there is no overlap (no cans of soda), the number of favorable outcomes \(=6 + 5=11\)

Step3: Calculate the probability

Probability \(P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{11}{23}\approx0.48\)

Answer:

\(0.48\)