Question

1. a woman whose father was color blind marries a man who is color blind. what are the chances that their offspring will be color blind? (note: the woman is not color blind.) punnett square image

the chance of the baby being color blind is 50%.
a. whats the probability they would have a child that is color blind? ____%
b. whats the probability they would have a child that is not color blind? ____%

Explanation:

Step1: Analyze the Punnett Square

The Punnett Square has 4 possible genotypes for the offspring: \(XX^C\), \(X^CX^C\), \(XY\), \(X^CY\). From the square, the color - blind genotypes (where the trait is expressed) are \(X^CX^C\) (female) and \(X^CY\) (male). Counting the number of color - blind genotypes: out of 4, 2 are color - blind (\(X^CX^C\) and \(X^CY\)).

Step2: Calculate Probability for Part (a)

Probability is the number of favorable outcomes (color - blind offspring) divided by the total number of outcomes. So, \(\frac{2}{4}\times100 = 50\%\).

Step3: Calculate Probability for Part (b)

The number of non - color - blind genotypes: out of 4, 2 are non - color - blind (\(XX^C\) and \(XY\)). So, \(\frac{2}{4}\times100=50\%\). Also, since the total probability is 100%, we can also calculate it as \(100\% - 50\%=50\%\).

Answer:

a. 50%
b. 50%