Question

1. a white flowered plant is crossed with a plant that is heterozygous for the trait. what are the genotypes and phenotype possibilities for the offspring? probabilities punnett square genotypes % phenotypes % % ff % ff % purple % white parents → f f f f

Explanation:

Step1: Determine the genotypes of the parents

Assume that the allele for purple flowers (\(F\)) is dominant over the allele for white flowers (\(f\)). A white - flowered plant has the genotype \(ff\) (since it needs two recessive alleles to express the white phenotype). The heterozygous plant has the genotype \(Ff\).

Step2: Create the Punnett square

	\(F\)	\(f\)
\(f\)	\(Ff\)	\(ff\)

Step3: Calculate the genotype and phenotype ratios

• Genotype ratios:
• \(Ff\): There are 2 out of 4 boxes with \(Ff\), so the percentage is \(\frac{2}{4}\times100\% = 50\%\)
• \(ff\): There are 2 out of 4 boxes with \(ff\), so the percentage is \(\frac{2}{4}\times100\%=50\%\)
• Phenotype ratios:
• Purple (\(Ff\)): Since \(F\) is dominant, plants with \(Ff\) will have purple flowers. The percentage is \(\frac{2}{4}\times 100\%=50\%\)
• White (\(ff\)): Plants with \(ff\) will have white flowers. The percentage is \(\frac{2}{4}\times100\% = 50\%\)

Answer:

• Genotypes: \(50\%\ Ff\) and \(50\%\ ff\)
• Phenotypes: \(50\%\) purple and \(50\%\) white