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Question
which weight can you use to replace x and keep the hanger balanced? 3 complete the statement. the hanger is balanced when x = \square. that means \square? is the solution of the equation x + 2 = 5.
Step1: Solve the equation \(x + 2=5\)
Subtract 2 from both sides of the equation.
$$x+2 - 2=5 - 2$$
Step2: Simplify the equation
Simplify left - hand side \(x+2 - 2=x\), and right - hand side \(5 - 2 = 3\).
So \(x = 3\).
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The hanger is balanced when \(x = 3\). That means \(3\) is the solution of the equation \(x + 2=5\).