Question

what is the probability of heterozygous offspring?

Explanation:

Step1: Count the total number of offspring

There are 4 boxes in the Punnett square, so the total number of offspring is \(n = 4\).

Step2: Count the number of heterozygous offspring

Heterozygous offspring have the genotype \(Bb\). There are 2 boxes with \(Bb\), so the number of heterozygous offspring is \(m=2\).

Step3: Calculate the probability

The probability \(P\) of an event is given by the formula \(P=\frac{m}{n}\). Substituting \(m = 2\) and \(n = 4\) into the formula, we get \(P=\frac{2}{4}=\frac{1}{2}=0.5 = 50\%\).

Answer:

50%