QUESTION IMAGE
Question
what are the most likely genotypes of two parents who are not albino and who have an albino child?
○ aa and aa
○ aa and aa
○ aa and aa
○ aa and aa
○ aa and aa
Step1: Determine the inheritance pattern
Albinism is a recessive trait. Let \(A\) represent the dominant allele (non - albino) and \(a\) represent the recessive allele (albino). An albino individual has the genotype \(aa\).
Step2: Analyze each option
- Option 1 (\(aa\) and \(AA\)):
The cross \(AA\times aa\) gives \(Aa\) offspring. All offspring will be non - albino (\(Aa\)).
- Option 2 (\(aa\) and \(aa\)):
Both parents are albino (\(aa\)). But the problem states that parents are not albino.
- Option 3 (\(AA\) and \(AA\)):
The cross \(AA\times AA\) gives \(AA\) offspring. All offspring will be non - albino (\(AA\)).
- Option 4 (\(AA\) and \(aa\)):
As in option 1, \(AA\times aa\) gives \(Aa\) offspring. All offspring will be non - albino (\(Aa\)).
- Option 5 (\(Aa\) and \(Aa\)):
Using the Punnett square for \(Aa\times Aa\):
| Gametes of Parent 1 | Gametes of Parent 2 | |
|---|---|---|
| \(A\) | \(AA\) (non - albino) | \(Aa\) (non - albino) |
| \(a\) | \(Aa\) (non - albino) | \(aa\) (albino) |
The probability of getting an \(aa\) (albino) child is \(\frac{1}{4}\), and the parents (\(Aa\)) are non - albino. So, the most likely genotypes of the parents are \(Aa\) and \(Aa\).
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Aa and Aa