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what is the equation of the trend line in the scatter plot? use the two…

Question

what is the equation of the trend line in the scatter plot?
use the two blue points to write the equation in slope - intercept form. write any coefficients as integers, proper fractions, or improper fractions in simplest form.
image img
options:
y = 50/80x + 40
y = 50/80x - 40
y = 5/8x + 40
y = 5/8x + 40

Explanation:

Step1: Identify the two blue points

From the scatter plot, the two blue points are \((0, 40)\) (the y - intercept) and \((80, 90)\).

Step2: Calculate the slope \(m\)

The slope formula is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Let \((x_1,y_1)=(0,40)\) and \((x_2,y_2)=(80,90)\). Then \(m=\frac{90 - 40}{80 - 0}=\frac{50}{80}=\frac{5}{8}\).

Step3: Write the equation in slope - intercept form

The slope - intercept form of a line is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. We know that \(m=\frac{5}{8}\) and \(b = 40\) (since the line crosses the y - axis at \((0,40)\)). So the equation of the line is \(y=\frac{5}{8}x + 40\).

Answer:

\(y=\frac{5}{8}x + 40\)