Question

a watermelon weighs 8,475 grams. a scale measured the weight with an error of 12% under the actual weight. what was the measured weight?
grams

Explanation:

Step1: Find the percentage of measured weight

The scale measures 12% under actual weight, so measured percentage is \(100\% - 12\% = 88\%\) or \(0.88\) in decimal.

Step2: Calculate measured weight

Multiply actual weight by measured percentage: \(8475\times0.88\)
\(8475\times0.88 = 8475\times\frac{88}{100}=8475\times\frac{22}{25}=\frac{8475\times22}{25}=339\times22 = 7458\)

Answer:

7458