Question

a volleyball players serving percentage is 75%. six of her serves are randomly selected. using the table, what is the probability that at most 4 of them were successes?

0.297
0.466
0.534
0.822

Explanation:

Step1: Understand the meaning of "at most 4"

"At most 4" means the number of successful serves is 0, 1, 2, 3, or 4.

Step2: Sum up the probabilities

We need to add the probabilities corresponding to 0, 1, 2, 3, and 4 successful serves.

$$P(X\leq4)=P(X = 0)+P(X=1)+P(X = 2)+P(X=3)+P(X = 4)$$

Substitute the values from the table:

$$P(X\leq4)=0.0002 + 0.004+0.033+0.132+0.297$$

$$P(X\leq4)=0.4662\approx0.466$$

Answer:

0.466