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vladimir rolls a six - sided number cube 36 times. if getting a 3 is a …

Question

vladimir rolls a six - sided number cube 36 times. if getting a 3 is a success, what is the probability of a success?
$\frac{1}{6}$
$\frac{1}{3}$
$\frac{2}{3}$
$\frac{5}{6}$

Explanation:

Step1: Identify possible outcomes

A six - sided number cube has 6 possible outcomes: 1, 2, 3, 4, 5, 6. So the total number of possible outcomes $n = 6$.

Step2: Identify successful outcomes

A success is getting a 3. There is only 1 way to get a 3, so the number of successful outcomes $m=1$.

Step3: Calculate probability

The probability of an event is given by the formula $P=\frac{\text{Number of successful outcomes}}{\text{Total number of possible outcomes}}$. Substituting $m = 1$ and $n=6$ into the formula, we get $P=\frac{1}{6}$.

Answer:

$\frac{1}{6}$ (corresponding to the first option)