Question

use the values \\( \log 128 \approx 2.1 \\) and \\( \log 4 \approx 0.6 \\) to find the approximate value of \\( \log_{4} 128 \\).
\\( \log_{4} 128 \approx \underline{quadquad}

the solution is

Explanation:

Step1: Apply change of base formula

$\log_{4}128 = \frac{\log 128}{\log 4}$

Step2: Substitute given values

$\frac{2.1}{0.6} = 3.5$

Answer:

3.5