Question

use the phenotypes of the f₁ progeny to deduce the genotype and phenotype of each parent plant. complete the table by dragging the correct label to the appropriate location. labels can be used once, more than once, or not at all. view available hint(s) (table with plant 1 - 4, columns: parent phenotype, parent genotype, f₁ progeny phenotypes from selfed parent; and drag - and - drop elements above the table)

Explanation:

To solve this, we analyze the F₁ progeny phenotypes from selfed parents to deduce parent phenotypes and genotypes (assuming a Mendelian inheritance context, likely for pea plants, e.g., seed color where green might be dominant/recessive based on ratios).

Plant 1:

• F₁ progeny: Only green. If selfed parent gives all green, the parent is likely homozygous for green (consistent with genotype G₁ and phenotype G₂? Wait, maybe G₂ is green phenotype. Wait, let's re-express:

Assume:

• If selfing a parent gives only green progeny, the parent is homozygous (so genotype G₁, phenotype G₂ (green)).

Plant 2:

• F₁ progeny: Green and yellow (ratio ~2:2 or 1:1? Wait, the image shows two green and two yellow? Wait, the table for Plant 2: F₁ progeny has two green, two yellow. So selfed parent is heterozygous (genotype G₁, phenotype G₂? Wait, maybe G₂ is green, and the parent with G₁ genotype (heterozygous) when selfed gives 3:1? Wait, no, Plant 2 has two green, two yellow (1:1? No, 2:2 is 1:1, but that's a test cross ratio. Wait, maybe the parent phenotypes:

Wait, the problem is about deducing parent phenotype (G₂) and genotype (G₁) by F₁ progeny. Let's go step by step:

Step 1: Plant 1

• F₁ progeny: All green (two green). So selfed parent must be homozygous (so genotype G₁, phenotype G₂ (green), since only green progeny).

Step 2: Plant 2

• F₁ progeny: Two green, two yellow. So selfed parent is heterozygous (genotype G₁, phenotype G₂ (green), because heterozygous selfing gives 3:1, but here maybe a typo or simplified. Wait, maybe G₂ is green, and the parent with G₁ (heterozygous) when selfed gives both colors.

Step 3: Plant 3

• F₁ progeny: One green, one yellow. So selfed parent is heterozygous? Wait, no—wait, maybe the parent phenotype (G₂) is green, genotype G₁ (heterozygous) for Plant 3? Wait, no, if selfed parent gives 1:1, it's a test cross, but selfing a heterozygous gives 3:1. Wait, maybe the labels: G₂ is the phenotype (e.g., green), G₁ is genotype (e.g., heterozygous or homozygous).

Step 4: Plant 4

• F₁ progeny: One green. So selfed parent is homozygous green (genotype G₁, phenotype G₂).

But the key is to match the labels. Since the task is to drag labels, but the final answer here (assuming the correct parent phenotypes and genotypes) would be:

For each plant, the parent phenotype is G₂ (green) and genotype G₁ (as per the table’s given genotype G₁ for all, so parent phenotype is G₂).

Answer:

For each plant (1 - 4), the parent phenotype is G₂ (the pink - labeled G₂) and genotype is G₁ (the blue - labeled G₁). So:

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