Question

use the formula to model the process of cellular respiration and complete the diagram. start by building the reactants and drawing a diagram of each molecule. remember the coefficient tells you how many of that molecule you need to build! once you build your reactants you can only use those atoms for your products. then, answer the questions that follow. \\(\ce{c6h12o6 + 6o2 -> 6co2 + 6h2o}\\) 8. how many total carbon atoms are in the reactants of respiration? \\(\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\) 9. how many total oxygen atoms are in the reactants of respiration? \\(\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\) 10 how many total hydrogen atoms are in the reactants of respiration? \\(\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\) 11 how many total carbon atoms are in the products of respiration? \\(\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\) 12. how many total oxygen atoms are in the products of respiration? \\(\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\_\\)

Explanation:

Step 1: Analyze Reactants for Carbon (Question 8)

The reactant is \( C_6H_{12}O_6 \) (glucose) and \( 6O_2 \). In \( C_6H_{12}O_6 \), the subscript of C is 6, and \( O_2 \) has no C. So total C atoms: \( 6\times1 = 6 \).

Step 2: Analyze Reactants for Oxygen (Question 9)

In \( C_6H_{12}O_6 \), O subscript is 6. In \( 6O_2 \), each \( O_2 \) has 2 O, so \( 6\times2 = 12 \). Total O: \( 6 + 12 = 18 \).

Step 3: Analyze Reactants for Hydrogen (Question 10)

In \( C_6H_{12}O_6 \), H subscript is 12. \( O_2 \) has no H. So total H: \( 12\times1 = 12 \).

Step 4: Analyze Products for Carbon (Question 11)

Product is \( 6CO_2 \) and \( 6H_2O \). In \( CO_2 \), C subscript is 1, and there are 6 \( CO_2 \). So total C: \( 6\times1 = 6 \).

Step 5: Analyze Products for Oxygen (Question 12)

In \( 6CO_2 \), each \( CO_2 \) has 2 O: \( 6\times2 = 12 \). In \( 6H_2O \), each \( H_2O \) has 1 O: \( 6\times1 = 6 \). Total O: \( 12 + 6 = 18 \).

Answer:

s:

1. 6
2. 18
3. 12
4. 6
5. 18