QUESTION IMAGE
Question
type the correct answer in each box.
in a game at an amusement park, a player can win 20 points, 25 points, or 30 points. the probability of winning these points is given in the table.
| points | 20 | 25 | 30 |
|---|
if jenny expects to win 22.5 points by playing the game once, the value of x is
and the value of y is
Step1: Recall Expected Value Formula
The expected value \( E(X) \) of a discrete random variable is given by \( E(X)=\sum x_iP(x_i) \), where \( x_i \) are the possible values and \( P(x_i) \) are their corresponding probabilities. Also, the sum of all probabilities must be 1, so \( 0.6 + x + y = 1 \), which implies \( x + y = 0.4 \).
Step2: Set Up Expected Value Equation
We know \( E(X) = 22.5 \), \( x_1 = 20, P(x_1)=0.6 \); \( x_2 = 25, P(x_2)=x \); \( x_3 = 30, P(x_3)=y \). So:
Simplify the left - hand side: \( 12+25x + 30y = 22.5 \), then \( 25x+30y=22.5 - 12=10.5 \).
Step3: Solve the System of Equations
We have the system:
- \( x + y=0.4\Rightarrow y = 0.4 - x \)
- \( 25x + 30y=10.5 \)
Substitute \( y = 0.4 - x \) into the second equation:
Expand: \( 25x + 12-30x = 10.5 \)
Combine like terms: \( - 5x=10.5 - 12=-1.5 \)
Solve for \( x \): \( x=\frac{- 1.5}{-5}=0.3 \)
Step4: Find the Value of y
Since \( y = 0.4 - x \) and \( x = 0.3 \), then \( y=0.4 - 0.3 = 0.1 \)
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The value of \( x \) is \( 0.3 \) and the value of \( y \) is \( 0.1 \)