Question

two water tanks are leaking water. the equation and the table each represent the gallons of water in the tank, y, as a function of time in minutes, x. how much water does tank a hold before it starts to leak? find the initial value. gallons tank a: y = 900 - 11x tank b: (table with minutes, x: 0,1,2,3 and water in tank (gal), y: 985,975,965,955)

Explanation:

Step1: Understand the initial value

The initial value of a function \( y = f(x) \) is the value of \( y \) when \( x = 0 \) (at the start, before any time has passed, \( x = 0 \) minutes).

Step2: Substitute \( x = 0 \) into the equation for Tank A

The equation for Tank A is \( y = 900 - 11x \). Substitute \( x = 0 \) into this equation:
\( y = 900 - 11(0) \)
\( y = 900 - 0 \)
\( y = 900 \)

Answer:

900