try these ones...
count the number of atoms of each element in the following compounds:
cuso₄
li₂co₃
al₂(so₄)₃
4na₂co₃

Question

Accepted Answer

# Explanation:
## Step1: Analyze $CuSO_4$
- **Copper ($Cu$)**: The sub - script for $Cu$ is $1$ (since $Cu$ is written as $Cu$ without a sub - script, it is assumed to be $1$).
- **Sulfur ($S$)**: The sub - script for $S$ is $1$.
- **Oxygen ($O$)**: The sub - script for $O$ is $4$.
- **Total number of atoms**: $1 + 1+4=6$

## Step2: Analyze $Li_2CO_3$
- **Lithium ($Li$)**: The sub - script for $Li$ is $2$.
- **Carbon ($C$)**: The sub - script for $C$ is $1$.
- **Oxygen ($O$)**: The sub - script for $O$ is $3$.
- **Total number of atoms**: $2 + 1+3=6$

## Step3: Analyze $Al_2(SO_4)_3$
- **Aluminum ($Al$)**: The sub - script for $Al$ is $2$.
- **Sulfur ($S$)**: Inside the parenthesis, the sub - script for $S$ is $1$, and the outer sub - script is $3$. So the number of $S$ atoms is $1\times3 = 3$.
- **Oxygen ($O$)**: Inside the parenthesis, the sub - script for $O$ is $4$, and the outer sub - script is $3$. So the number of $O$ atoms is $4\times3=12$.
- **Total number of atoms**: $2+3 + 12=17$

## Step4: Analyze $4Na_2CO_3$
- **Sodium ($Na$)**: The sub - script for $Na$ is $2$, and there is a coefficient of $4$. So the number of $Na$ atoms is $2\times4 = 8$.
- **Carbon ($C$)**: The sub - script for $C$ is $1$, and  the coefficient is $4$. So the number of $C$ atoms is $1\times4=4$.
- **Oxygen ($O$)**: The sub - script for $O$ is $3$, and the coefficient is $4$. So the number of $O$ atoms is $3\times4 = 12$.
- **Total number of atoms**: $8+4+12=24$

# Answer:
| Compound | Elements Present | Number of Atoms |
|---|---|---|
| $CuSO_4$ | $Cu$ | $1$ |
|  | $S$ | $1$ |
|  | $O$ | $4$ |
|  | Total Number of Atoms: | $6$ |
| $Li_2CO_3$ | $Li$ | $2$ |
|  | $C$ | $1$ |
|  | $O$ | $3$ |
|  | Total Number of Atoms: | $6$ |
| $Al_2(SO_4)_3$ | $Al$ | $2$ |
|  | $S$ | $3$ |
|  | $O$ | $12$ |
|  | Total Number of Atoms: | $17$ |
| $4Na_2CO_3$ | $Na$ | $8$ |
|  | $C$ | $4$ |
|  | $O$ | $12$ |
|  | Total Number of Atoms: | $24$ |

Compound	Elements Present	Number of Atoms
	\(S\)	\(1\)
	\(O\)	\(4\)
	Total Number of Atoms:	\(6\)
\(Li_2CO_3\)	\(Li\)	\(2\)
	\(C\)	\(1\)
	\(O\)	\(3\)
	Total Number of Atoms:	\(6\)
\(Al_2(SO_4)_3\)	\(Al\)	\(2\)
	\(S\)	\(3\)
	\(O\)	\(12\)
	Total Number of Atoms:	\(17\)
\(4Na_2CO_3\)	\(Na\)	\(8\)
	\(C\)	\(4\)
	\(O\)	\(12\)
	Total Number of Atoms:	\(24\)

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QUESTION IMAGE

Question

Explanation:

Step1: Analyze \(CuSO_4\)

Step2: Analyze \(Li_2CO_3\)

Step3: Analyze \(Al_2(SO_4)_3\)

Step4: Analyze \(4Na_2CO_3\)

Answer: