Question

transcribe the following strand of dna
tacgagccaatacccatt

translate the strand above

Explanation:

Step1: Transcribe DNA to mRNA

In transcription, DNA's thymine (T) is replaced by uracil (U) in mRNA, and adenine (A) pairs with uracil (U), cytosine (C) pairs with guanine (G), guanine (G) pairs with cytosine (C), and thymine (T) pairs with adenine (A) in DNA - mRNA pairing.
Given DNA strand: TACGAGCCAATACCCATT
So mRNA strand: AUGCUC GGUUAUGGGUAA (grouped in codons for translation later, but first transcribe each base: T→A, A→U, C→G, G→C, A→U, G→C, C→G, C→G, A→U, A→U, T→A, A→U, C→G, C→G, C→G, A→U, T→A, T→A)
Wait, let's do it base by base:
DNA: T A C G A G C C A A T A C C C A T T
mRNA: A U G C U C G G U U A U G G G U A A (correcting the earlier grouping mistake. Let's list each base:
T (DNA) → A (mRNA)
A (DNA) → U (mRNA)
C (DNA) → G (mRNA)
G (DNA) → C (mRNA)
A (DNA) → U (mRNA)
G (DNA) → C (mRNA)
C (DNA) → G (mRNA)
C (DNA) → G (mRNA)
A (DNA) → U (mRNA)
A (DNA) → U (mRNA)
T (DNA) → A (mRNA)
A (DNA) → U (mRNA)
C (DNA) → G (mRNA)
C (DNA) → G (mRNA)
C (DNA) → G (mRNA)
A (DNA) → U (mRNA)
T (DNA) → A (mRNA)
T (DNA) → A (mRNA)
So mRNA is AUGCUC GGUUAUGGGUAA (now group into codons: AUG, CUC, GGU, UAU, GGG, UAA)

Step2: Translate mRNA to amino acids

Now, use the genetic code table.

• AUG: Methionine (start codon)
• CUC: Leucine
• GGU: Glycine
• UAU: Tyrosine
• GGG: Glycine
• UAA: Stop codon (terminates translation)

So the amino acid sequence is Methionine - Leucine - Glycine - Tyrosine - Glycine (and then stop, so the polypeptide is Met - Leu - Gly - Tyr - Gly)

Answer:

Transcribed mRNA: $\boldsymbol{AUGCUC GGUUAUGGGUAA}$ (or grouped as codons: AUG, CUC, GGU, UAU, GGG, UAA)
Translated amino acid sequence: Methionine - Leucine - Glycine - Tyrosine - Glycine (with a stop codon UAA at the end, so the protein sequence is Met - Leu - Gly - Tyr - Gly)