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Question
time (min) | water left in pool (gal)\
10 | 80\
20 | 60\
30 | 40\
40 | 20
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The relationship is linear. The slope \(m=\frac{60 - 80}{20 - 10}=- 2\). Using the point - slope form \(y - y_1=m(x - x_1)\) with \((x_1,y_1)=(10,80)\), we get \(y-80=-2(x - 10)\), which simplifies to \(y=-2x + 100\)