Question

there are 8 colored cubes in a bag. three are red, three are green, and two are blue. a cube is drawn but is not replaced, and then another cube is drawn. what is the probability that a red cube is drawn first, and then a green cube? \\(\frac{\square}{\square}\\) probability

Explanation:

Step1: Probability of red first

There are 3 red cubes out of 8 total. So probability of red first is $\frac{3}{8}$.

Step2: Probability of green second (no replacement)

After drawing a red, there are 7 cubes left, with 3 green. So probability of green second is $\frac{3}{7}$.

Step3: Multiply the probabilities

To find the probability of both events, multiply the two probabilities: $\frac{3}{8} \times \frac{3}{7} = \frac{9}{56}$.

Answer:

$\frac{9}{56}$