Question

task: a. find the measure of center for the height of the students mean: __ median: mode: range: sd: b. find the five number summary for the height of the students min: q1: median: q3: max: interquartile range: q3 - q1 lower outlier: =q1-(1.5)(iqr) upper outlier: __ = q3+(1.5)(iqr)

Explanation:

Step1: Since no data is provided for student heights

We cannot perform calculations.

Step2: For mean, we sum all data points and divide by number of data points.

$\text{Mean}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$

Step3: To find median, we order data and find middle - value.

If $n$ is odd, median is middle number; if $n$ is even, it's average of two middle numbers.

Step4: Mode is the most frequently occurring value.

Step5: Range is difference between maximum and minimum values.

$\text{Range}=\text{Max}-\text{Min}$

Step6: Standard deviation (SD) measures spread of data.

$\text{SD}=\sqrt{\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}}$ (sample standard deviation)

Step7: For five - number summary:

Min is smallest value, Q1 is first quartile (25th percentile), median (second quartile, 50th percentile), Q3 is third quartile (75th percentile), Max is largest value.

Step8: Interquartile range (IQR) is $IQR = Q3 - Q1$.

Step9: Lower outlier is $Q1-(1.5)(IQR)$.

Step10: Upper outlier is $Q3+(1.5)(IQR)$.

Answer:

Since no data on student heights is given, we cannot provide numerical answers for mean, median, mode, range, SD, five - number summary, IQR, lower outlier, and upper outlier.