Question

the table summarizes results from 987 pedestrian deaths that were caused by automobile accidents.

if one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was not intoxicated.
report the answer as a percent rounded to one decimal place accuracy. you need not enter the \%\ symbol.
prob = %
question help: video 1 video 2
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Explanation:

Step1: Calculate the number of favorable cases

• Number of pedestrians intoxicated: \(52 + 254=306\)
• Number of drivers not intoxicated: \(254 + 600 = 854\)
• Number of cases where pedestrian is intoxicated and driver is not intoxicated: \(254\)
• Using the formula \(P(A\cup B)=P(A)+P(B)-P(A\cap B)\)
• \(n(A\cup B)=(306)+(854)-254 = 906\)

Step2: Calculate the probability

• Total number of cases \(n = 987\)
• Probability \(P=\frac{906}{987}\approx0.918\)
• Convert to percentage: \(0.918\times100 = 91.8\) (Wrong, let's use another approach)

Let's use the formula \(P(A\cup B)=\frac{\text{Number of elements in }A\cup B}{\text{Total number of elements}}\)

Number of pedestrians intoxicated \(n_1=52 + 254=306\)

Number of drivers not intoxicated \(n_2=254+600 = 854\)

Number of pedestrians intoxicated and drivers not intoxicated \(n_{12}=254\)

\(n(A\cup B)=n_1 + n_2 - n_{12}=306+854 - 254=906\)

\(P=\frac{906}{987}\approx 0.855\)

Convert to percentage: \(0.855\times100 = 85.5\)

Answer:

85.5