Question

suzie wants to make two different solutions of salt water for a science experiment. there is a proportional relationship between the volume of each solution and the amount of salt she puts in it. this table shows the amount of salt in solution a. this graph shows the amount of salt in solution b. which solution is less salty? solution a solution b how much salt would there be in 1.2 liters of that solution? grams

Explanation:

Step1: Find the unit rate for Solution A

The unit rate (grams of salt per liter) for Solution A is calculated by dividing the amount of salt by the volume. For example, using the first row: \( \frac{9}{0.3}=30\) grams per liter.

Step2: Find the unit rate for Solution B

From the graph, when \(x = 0.4\) liters (volume), \(y=20\) grams (salt). The unit rate is \( \frac{20}{0.4} = 50\) grams per liter.
Since \(30<50\), Solution A is less salty.

Step3: Calculate the amount of salt in 1.2 liters of Solution A

Using the unit - rate formula \(y = kx\) (where \(k = 30\) for Solution A and \(x = 1.2\)). Then \(y=30\times1.2\)

$$y = 30\times1.2=36$$

Answer:

Solution A is less salty. There are 36 grams of salt in 1.2 liters of Solution A.