Question

a supersonic jet flew east at a constant velocity for a total of 6 hours. in one - third of that time, it flew 2,600 kilometers. what was the jets velocity? write your answer as a whole number. \boxed{} kilometers per hour to the east submit

Explanation:

Step1: Find the time duration

One - third of 6 hours is calculated as $\frac{1}{3}\times6 = 2$ hours.

Step2: Calculate the velocity

Velocity is defined as the distance traveled divided by the time taken. The formula for velocity $v$ is $v=\frac{d}{t}$, where $d$ is the distance and $t$ is the time.
We know that $d = 2600$ kilometers and $t = 2$ hours.
Substituting these values into the formula, we get $v=\frac{2600}{2}=1300$ kilometers per hour.

Answer:

1300