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4. a student worked out at a gym continuously for 50 minutes. the graph…

Question

  1. a student worked out at a gym continuously for 50 minutes. the graph shows the remaining percentage of the workout as a linear function of x, the time in minutes. student’s workout graph of a line from (0,100) to (50,0) with y-axis labeled percentage remaining and x-axis labeled minutes what is the rate of change in percentage remaining with respect to the minutes? rate of change = ______

Explanation:

Step1: Identify two points

The graph passes through (0, 100) and (50, 0).

Step2: Use rate of change formula

Rate of change (slope) is $\frac{y_2 - y_1}{x_2 - x_1}$. Substitute $x_1 = 0, y_1 = 100, x_2 = 50, y_2 = 0$. So $\frac{0 - 100}{50 - 0}=\frac{-100}{50}=-2$.

Answer:

-2