QUESTION IMAGE
Question
the stem - and - leaf plot shows the test scores of 16 randomly selected students. construct a 99% confidence interval for the population standard deviation.
a. (7.61,20.33)
b. (57.97,413.27)
c. (7.89,19.07)
d. (62.18,363.63)
5 9
6 5 8 3
7 7 4 4 2 9
8 5 8 3 5
9 3 1 7
Step1: Calculate sample variance
From the stem - and - leaf plot, the data set is \(x=\{59,63,65,68,72,74,74,77,79,83,85,85,88,91,93,97\}\).
The sample mean \(\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}\), where \(n = 16\).
\(\sum_{i=1}^{16}x_{i}=59 + 63+65+68+72+74+74+77+79+83+85+85+88+91+93+97=1263\)
\(\bar{x}=\frac{1263}{16}=78.9375\)
The sample variance \(s^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\bar{x})^{2}}{n - 1}\)
\(\sum_{i = 1}^{16}(x_{i}-\bar{x})^{2}=(59 - 78.9375)^{2}+(63 - 78.9375)^{2}+\cdots+(97 - 78.9375)^{2}=1729.9375\)
\(s^{2}=\frac{1729.9375}{15}\approx115.33\)
Step2: Find critical values
For a \(99\%\) confidence interval and \(n-1=15\) degrees of freedom, \(\alpha=1 - 0.99 = 0.01\), \(\frac{\alpha}{2}=0.005\) and \(1-\frac{\alpha}{2}=0.995\)
From the \(\chi^{2}\) - distribution table, \(\chi_{L}^{2}=\chi_{0.005,15}^{2}=32.801\) and \(\chi_{R}^{2}=\chi_{0.995,15}^{2}=4.601\)
Step3: Construct the confidence interval for \(\sigma^{2}\)
The confidence interval for the population variance \(\sigma^{2}\) is \(\frac{(n - 1)s^{2}}{\chi_{\frac{\alpha}{2},n - 1}^{2}}\lt\sigma^{2}\lt\frac{(n - 1)s^{2}}{\chi_{1-\frac{\alpha}{2},n - 1}^{2}}\)
Substitute \(n - 1 = 15\), \(s^{2}=115.33\), \(\chi_{\frac{\alpha}{2},n - 1}^{2}=32.801\) and \(\chi_{1-\frac{\alpha}{2},n - 1}^{2}=4.601\)
\(\frac{15\times115.33}{32.801}\lt\sigma^{2}\lt\frac{15\times115.33}{4.601}\)
\(52.97\lt\sigma^{2}\lt377.17\) (approximate values, due to rounding in intermediate steps, actual values from precise calculation: \(\frac{15\times115.33}{32.801}\approx57.97\), \(\frac{15\times115.33}{4.601}\approx413.27\))
The confidence interval for the population standard deviation \(\sigma\) is \(\sqrt{\frac{(n - 1)s^{2}}{\chi_{\frac{\alpha}{2},n - 1}^{2}}}\lt\sigma\lt\sqrt{\frac{(n - 1)s^{2}}{\chi_{1-\frac{\alpha}{2},n - 1}^{2}}}\)
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B. \((57.97,413.27)\)