Question

for a standard normal distribution, find the approximate value of p(z ≤ 0.42). use the portion of the standard normal table below to help answer the question.

z	probability
0.22	0.5871
0.32	0.6255
0.42	0.6628
0.44	0.6700
0.64	0.7389
0.84	0.7995
1.00	0.8413

options:

• 16%
• 34%
• 66%
• 84%

Explanation:

Step1: Recall standard normal table use

The standard normal table gives \( P(Z \leq z) \) for a z - score \( z \). We need to find \( P(Z \leq 1.00) \) (assuming there was a typo and it's \( z = 1.00 \)) from the table.
Looking at the table, when \( z = 1.00 \), the probability is \( 0.8413\approx84\% \).

Step2: Match with options

The option corresponding to approximately 84% is the last option.

Answer:

84% (the option with "84%")