Question

spooner has a heterozygous genotype for his tongue (tt), but wendy has the recessive trait of no tongue (tt).
spooner
wendy
phenotype probability (%)
tongue:
no tongue:

Explanation:

Step1: Count total genotypes

From the Punnett square, there are 4 possible genotypes: Tt, tt, Tt, tt. So total number of outcomes is 4.

Step2: Count Tongue (Tt) genotypes

The number of Tt (tongue) genotypes is 2. Probability for tongue is $\frac{2}{4} \times 100\% = 50\%$.

Step3: Count No tongue (tt) genotypes

The number of tt (no tongue) genotypes is 2. Probability for no tongue is $\frac{2}{4} \times 100\% = 50\%$.

Answer:

Tongue: 50%
No tongue: 50%