Question

if the side of a cubical cell doubled, what would the cell then require? select all the correct answers.
a. eight times more nutrients
b. to excrete eight times more waste
c. four times more nutrients
d. to excrete four times more waste

Explanation:

Step1: Calculate the volume of a cube

The volume formula of a cube is \(V = s^3\), where \(s\) is the side length of the cube.

Step2: Analyze the change in volume when the side length is doubled

Let the original side length be \(s\), and the new side length be \(2s\). The original volume \(V_1=s^3\), and the new volume \(V_2=(2s)^3 = 8s^3\).
Since the amount of nutrients a cell needs and the amount of waste it excretes are related to its volume (assuming a uniform distribution of metabolic activities throughout the cell volume), when the volume becomes \(8\) times the original volume (\(V_2 = 8V_1\)), the cell will require \(8\) times more nutrients and need to excrete \(8\) times more waste.

Answer:

A. eight times more nutrients, B. to excrete eight times more waste