Question

c. show the cross of a white-eyed female (x^rx^r) with a red-eyed male (x^ry).
d. what is the chance that the above cross will yield offspring with red eyes? ____%

Explanation:

Part c:

Step1: Determine Gametes

The white - eyed female (\(X^{r}X^{r}\)) can only produce \(X^{r}\) gametes. The red - eyed male (\(X^{R}Y\)) can produce \(X^{R}\) and \(Y\) gametes.

Step2: Set up Punnett Square

	\(X^{r}\)	\(X^{r}\)
\(Y\)	\(X^{r}Y\)	\(X^{r}Y\)

Part d:

Step1: Analyze Offspring Genotypes

From the Punnett square, the offspring genotypes are \(X^{R}X^{r}\) (red - eyed females), \(X^{R}X^{r}\) (red - eyed females), \(X^{r}Y\) (white - eyed males), and \(X^{r}Y\) (white - eyed males).

Step2: Calculate Probability

Out of 4 offspring, 2 have red eyes (\(X^{R}X^{r}\)). The probability is \(\frac{2}{4}\times100 = 50\%\).

Answer:

c. Punnett square as above. d. 50%