Question

in seals, the gene for the length of the whiskers has two alleles. long hair is dominant over short hair. what percentage of offspring would be expected to have short whiskers from the cross of two long - whiskered seals, one that is homozygous dominant and one that is heterozygous?
75%
25%
100%
0%

Explanation:

Step1: Define alleles

Let \(L\) represent the dominant allele (long whiskers) and \(l\) represent the recessive allele (short whiskers). The homozygous dominant seal has genotype \(LL\), and the heterozygous seal has genotype \(Ll\).

Step2: Set up Punnett square

The possible gametes from the \(LL\) seal are all \(L\). The possible gametes from the \(Ll\) seal are \(L\) and \(l\). The Punnett square is:

	\(L\)	\(L\)
\(l\)	\(Ll\)	\(Ll\)

Step3: Analyze genotypes

The offspring genotypes are \(LL\) and \(Ll\). Since \(L\) (long whiskers) is dominant over \(l\) (short whiskers), all offspring (\(LL\) and \(Ll\)) will have long whiskers.

Answer:

\(0\%\)