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Question
- at a school festival, a photo booth is selling photos. they collect $40 for every 16 photos they sell. which statement correctly identifies both the slope and its meaning in the situation? a. the slope is \ LXI0 , so the amount of money made for every photo is $0.40. c. the slope is \\(\frac{2}{5}\\), so to make $1, they have to sell 0.40 photos. d. the slope is \ LXI2 , so to make $1, they have to sell 2.5 photos. chart: money collected ($) on x - axis (0,20,40,60,80,100), number of photos sold on y - axis (0,8,16,24,32,40,48), with a line and plotted points
Step1: Calculate the slope
The slope \( m \) of a line is given by \( m=\frac{\text{change in } y}{\text{change in } x} \). Here, \( y \) is Money Collected (\$) and LXI3 is Number of Photos Sold. From the graph, when LXI4 , LXI5 . So slope LXI6 ? Wait, no, wait: Wait, the axes: Number of Photos Sold is on the y - axis? Wait, no, looking at the graph: the vertical axis (y - axis) is Number of Photos Sold? Wait, no, the labels: "Money Collected (\$)" is horizontal (x - axis?), no, wait the graph: the bottom axis is Money Collected (\$) (from 0 to 100), and the left axis is Number of Photos Sold (from 0 to 48). Wait, so the line goes from (0,0) to (40,16)? Wait, no, the dot is at (20,8), (60,24), (80,32). Wait, let's take two points: (20,8) and (40,16). Then slope LXI7 . Wait, that's the slope. Wait, slope is LXI8 ? Wait, no, the slope formula: if LXI9 is number of photos and LXI10 is money, then slope LXI11 . Let's take (20,8) and (40,16): LXI12 . Wait, but let's check the problem statement: they collect \$40 for every 16 photos. So the rate is \( \frac{40}{16}=\frac{5}{2}=2.5 \) dollars per photo? Wait, no, maybe I mixed up x and y. Let's re - define: Let \( x \) be number of photos, \( y \) be money collected. Then when \( x = 16 \), \( y = 40 \). So slope \( m=\frac{y}{x}=\frac{40}{16}=\frac{5}{2} \). Wait, now I'm confused. Wait the options: Option C says "The slope is \( \frac{2}{5} \), so to make \$1, they have to sell 0.40 photos." Wait, if slope is LXI20 , then slope LXI21 . So if LXI22 is money, LXI23 is photos, then slope LXI24 . From (20,8): LXI25 . So for LXI26 (money = \$1), \( y=\frac{2}{5}\times1 = 0.4 \) photos. Wait, but the problem says "they collect \$40 for every 16 photos", so \$40 per 16 photos, so per \$1, photos sold is LXI28 photos. And the slope: if we model LXI29 , LXI30 , then LXI31 , so LXI32 . So slope LXI33 . So to make \$1, photos sold is \( \frac{2}{5}\times1 = 0.4 \) photos. So option C: "The slope is \( \frac{2}{5} \), so to make \$1, they have to sell 0.40 photos." Wait, but let's check the slope calculation again. Let's take two points: when money is \$20, photos are 8; when money is \$40, photos are 16. So slope LXI36 . So the slope is LXI37 , and the meaning: slope is LXI38 , so for each dollar, the number of photos sold is LXI39 photos. So option C is correct? Wait, no, option C says "The slope is LXI40 , so to make \$1, they have to sell 0.40 photos." Yes, because \( \frac{2}{5}\times1 = 0.4 \). Let's check other options: Option A: slope \( \frac{2}{5} \), money per photo: \( \frac{5}{2}=2.5 \) dollars per photo, but slope here is \( \frac{\text{money}}{\text{photo}} \)? No, if slope is \( \frac{\text{money}}{\text{photo}} \), then \( m=\frac{40}{16}=\frac{5}{2} \), but the option A says slope \( \frac{2}{5} \), which is wrong. Option B: slope \( \frac{5}{2} \), money per photo: \( \frac{5}{2}=2.5 \) dollars per photo, but slope \( \frac{5}{2} \) would be \( \frac{\text{money}}{\text{photo}} \)…
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C. The slope is \(\frac{2}{5}\), so to make \$1, they have to sell 0.40 photos.