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8. at a school festival, a photo booth is selling photos. they collect …

Question

  1. at a school festival, a photo booth is selling photos. they collect $40 for every 16 photos they sell. which statement correctly identifies both the slope and its meaning in the situation? a. the slope is \LXI0, so the amount of money made for every photo is $0.40. c. the slope is \\(\frac{2}{5}\\), so to make $1, they have to sell 0.40 photos. d. the slope is \LXI2, so to make $1, they have to sell 2.5 photos. chart: money collected ($) on x - axis (0,20,40,60,80,100), number of photos sold on y - axis (0,8,16,24,32,40,48), with a line and plotted points

Explanation:

Step1: Calculate the slope

The slope \( m \) of a line is given by \( m=\frac{\text{change in } y}{\text{change in } x} \). Here, \( y \) is Money Collected (\$) and LXI3 is Number of Photos Sold. From the graph, when LXI4, LXI5. So slope LXI6? Wait, no, wait: Wait, the axes: Number of Photos Sold is on the y - axis? Wait, no, looking at the graph: the vertical axis (y - axis) is Number of Photos Sold? Wait, no, the labels: "Money Collected (\$)" is horizontal (x - axis?), no, wait the graph: the bottom axis is Money Collected (\$) (from 0 to 100), and the left axis is Number of Photos Sold (from 0 to 48). Wait, so the line goes from (0,0) to (40,16)? Wait, no, the dot is at (20,8), (60,24), (80,32). Wait, let's take two points: (20,8) and (40,16). Then slope LXI7. Wait, that's the slope. Wait, slope is LXI8? Wait, no, the slope formula: if LXI9 is number of photos and LXI10 is money, then slope LXI11. Let's take (20,8) and (40,16): LXI12. Wait, but let's check the problem statement: they collect \$40 for every 16 photos. So the rate is \( \frac{40}{16}=\frac{5}{2}=2.5 \) dollars per photo? Wait, no, maybe I mixed up x and y. Let's re - define: Let \( x \) be number of photos, \( y \) be money collected. Then when \( x = 16 \), \( y = 40 \). So slope \( m=\frac{y}{x}=\frac{40}{16}=\frac{5}{2} \). Wait, now I'm confused. Wait the options: Option C says "The slope is \( \frac{2}{5} \), so to make \$1, they have to sell 0.40 photos." Wait, if slope is LXI20, then slope LXI21. So if LXI22 is money, LXI23 is photos, then slope LXI24. From (20,8): LXI25. So for LXI26 (money = \$1), \( y=\frac{2}{5}\times1 = 0.4 \) photos. Wait, but the problem says "they collect \$40 for every 16 photos", so \$40 per 16 photos, so per \$1, photos sold is LXI28 photos. And the slope: if we model LXI29, LXI30, then LXI31, so LXI32. So slope LXI33. So to make \$1, photos sold is \( \frac{2}{5}\times1 = 0.4 \) photos. So option C: "The slope is \( \frac{2}{5} \), so to make \$1, they have to sell 0.40 photos." Wait, but let's check the slope calculation again. Let's take two points: when money is \$20, photos are 8; when money is \$40, photos are 16. So slope LXI36. So the slope is LXI37, and the meaning: slope is LXI38, so for each dollar, the number of photos sold is LXI39 photos. So option C is correct? Wait, no, option C says "The slope is LXI40, so to make \$1, they have to sell 0.40 photos." Yes, because \( \frac{2}{5}\times1 = 0.4 \). Let's check other options: Option A: slope \( \frac{2}{5} \), money per photo: \( \frac{5}{2}=2.5 \) dollars per photo, but slope here is \( \frac{\text{money}}{\text{photo}} \)? No, if slope is \( \frac{\text{money}}{\text{photo}} \), then \( m=\frac{40}{16}=\frac{5}{2} \), but the option A says slope \( \frac{2}{5} \), which is wrong. Option B: slope \( \frac{5}{2} \), money per photo: \( \frac{5}{2}=2.5 \) dollars per photo, but slope \( \frac{5}{2} \) would be \( \frac{\text{money}}{\text{photo}} \)…

Answer:

C. The slope is \(\frac{2}{5}\), so to make \$1, they have to sell 0.40 photos.