Question

a sample of 10 students were asked how many minutes they spent reading on a specific day. the number of minutes each student spent reading is recorded in the table below. youre trying to find the mean absolute deviation for this sample. start by recording the distance from the mean, 29, for each student in the sample. number of minutes spent reading minutes 41 34 38 23 31 17 15 27 25 39 distance from 29

Explanation:

Step1: Calculate distance for 41

The distance from a number \( x \) to the mean \( \mu \) is \( |x - \mu| \). For \( x = 41 \) and \( \mu = 29 \), we calculate \( |41 - 29| = |12| = 12 \).

Step2: Calculate distance for 34

For \( x = 34 \), \( |34 - 29| = |5| = 5 \).

Step3: Calculate distance for 38

For \( x = 38 \), \( |38 - 29| = |9| = 9 \).

Step4: Calculate distance for 23

For \( x = 23 \), \( |23 - 29| = | - 6| = 6 \).

Step5: Calculate distance for 31

For \( x = 31 \), \( |31 - 29| = |2| = 2 \).

Step6: Calculate distance for 17

For \( x = 17 \), \( |17 - 29| = | - 12| = 12 \).

Step7: Calculate distance for 15

For \( x = 15 \), \( |15 - 29| = | - 14| = 14 \).

Step8: Calculate distance for 27

For \( x = 27 \), \( |27 - 29| = | - 2| = 2 \).

Step9: Calculate distance for 25

For \( x = 25 \), \( |25 - 29| = | - 4| = 4 \).

Step10: Calculate distance for 39

For \( x = 39 \), \( |39 - 29| = |10| = 10 \).

Answer:

The distances from 29 (from left to right) are: 12, 5, 9, 6, 2, 12, 14, 2, 4, 10