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ronald fast food randomly selected 20% of locations and asked the manag…

Question

ronald fast food randomly selected 20% of locations and asked the manager about the most popular meat. of the locations surveyed, beef is the most popular meat at 4 locations. based on the data, what is the most reasonable estimate of the number of ronald fast food locations where the most popular meat is beef? choose 1 answer: a 4 b 12 c 16 d 20

Explanation:

Step1: Let the total number of locations be \(x\).

The number of surveyed locations is \(0.2x\).

Step2: Set up a proportion.

If in the surveyed \(20\%\) (or \(0.2\)) of the locations, the number of locations where beef is popular is \(4\). Let the total number of locations where beef is popular be \(y\). Assuming the proportion holds for the whole population, and if we assume the sample is representative, we can use the fact that the proportion of beef - popular locations in the sample is the same as in the whole. Since the sample is \(20\%\) of the total locations, and in the sample, the number of beef - popular locations is \(4\). If we assume the proportion is consistent, and we can think of it as \(4\) is \(20\%\) (or \(\frac{1}{5}\)) of the total number of beef - popular locations. Mathematically, if \(y\) is the total number of beef - popular locations, and we know that \(4 = 0.2y\).

Step3: Solve the equation \(4 = 0.2y\) for \(y\).

Using the formula \(y=\frac{4}{0.2}\). Since \(\frac{4}{0.2}=\frac{4}{\frac{1}{5}} = 4\times5\).

Answer:

\(20\) (Option D)