Question

robin and evelyn are playing a target game. the object of the game is to get an object as close to the center as possible. each players score is the number of centimeters away from the center. robin and evelyns results from five rounds are shown. robins scores: 99, 108, 102, 107, 119. evelyns scores: 125, 137, 138, 145, 145. the mean of robins scores is 107. what is the mean of evelyns scores?

Explanation:

Step1: Recall the mean formula

The mean formula is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $\bar{x}$ is the mean, $x_{i}$ are the data - points, and $n$ is the number of data - points. We know for Robin, $\bar{x}_{Robin}=107$ and $n = 5$, and the scores are $x_{1}=99,x_{2}=108,x_{3}=102,x_{4}=107,x_{5}=119$. We want to find the mean of Evelyn's scores. Evelyn's scores are $x_{1}=125,x_{2}=137,x_{3}=138,x_{4}=145,x_{5}=145$.

Step2: Calculate the sum of Evelyn's scores

$\sum_{i = 1}^{5}x_{i}=125 + 137+138+145+145=690$.

Step3: Calculate the mean of Evelyn's scores

Since $n = 5$, using the mean formula $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, we have $\bar{x}=\frac{690}{5}=138$.

Answer:

138