Question

a research study asked 2368 homeowners how many bedrooms were in their homes. the results are shown in the table below. what is the probability that a homeowner choses at bedrooms?

number of bedrooms	number of homeowners
3	616
4	829
5 or more	355

• a: about 15%
• b: about 35%
• c: about 24%
• d: about 25%

Explanation:

Step1: Identify the relevant group

Assuming the question is about "5 or more" (since the options are percentages and the table has that group). The number of homeowners with 5 or more bedrooms is 355. Total homeowners: 2368.

Step2: Calculate the probability

Probability = (Number of homeowners with 5 or more bedrooms) / (Total number of homeowners) = \( \frac{355}{2368} \approx 0.15 \) or 15%. Wait, but maybe the question was about "2 or less"? Let's check: \( \frac{568}{2368} \approx 0.24 \), which is about 24% (option C). Wait, the original question's "chooses at" is cut off, but likely "5 or more" or "2 or less". Let's recalculate for "5 or more": \( 355 \div 2368 \approx 0.15 \) (15%, option A). For "2 or less": \( 568 \div 2368 \approx 0.24 \) (24%, option C). Maybe the question is "5 or more". Let's confirm:

Total homeowners: 568 + 616 + 829 + 355 = 2368 (correct).

For "5 or more": \( \frac{355}{2368} \approx 0.15 \) (15%), so option A. But if it's "2 or less", it's ~24% (option C). Wait, maybe the question was "chooses at random has 5 or more bedrooms". Let's proceed with that.

Step1: Define the formula

Probability = (Number of favorable outcomes) / (Total number of outcomes)

Step2: Substitute values

Favorable (5 or more): 355, Total: 2368

Step3: Calculate

\( \frac{355}{2368} \approx 0.15 \) (15%)

Answer:

A. about 15%