Question

to rent a certain meeting room, a college charges a reservation fee of $18 and an additional fee of $6 per hour. the chemistry club wants to spend at most $60 on renting the room. what are the possible numbers of hours the chemistry club could rent the meeting room? use t for the number of hours. write your answer as an inequality solved for t.

Explanation:

Step1: Set up the inequality

The total cost is the reservation fee plus the hourly fee times the number of hours. The reservation fee is $18$ and the hourly fee is $6$ per hour. The club wants to spend at most $60$. So the inequality is $18 + 6t\leq60$.

Step2: Subtract 18 from both sides

Subtract 18 from both sides of the inequality: $18+6t - 18\leq60 - 18$. This simplifies to $6t\leq42$.

Step3: Divide both sides by 6

Divide both sides of the inequality $6t\leq42$ by 6. Using the rule $\frac{6t}{6}\leq\frac{42}{6}$, we get $t\leq7$.

Answer:

$t\leq7$