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rebecca surveyed the students at her school to find out which cellphone…

Question

rebecca surveyed the students at her school to find out which cellphone company they use. her results are listed in the table.

company acompany bcompany ctotal
sophomore34153685
junior244334101
senior18423090
total103110140353

what is the probability that a randomly chosen student is a junior who uses company b?

a. \\(\frac{43}{353}\\)

b. \\(\frac{101}{353}\\)

c. \\(\frac{110}{353}\\)

d. \\(\frac{43}{101}\\)

e. \\(\frac{43}{110}\\)

Explanation:

Step1: Identify the number of junior students using Company B

From the table, the number of junior students using Company B is 43.

Step2: Identify the total number of students

The total number of students surveyed is 353 (from the "Total" row and "Total" column).

Step3: Calculate the probability

The probability is the number of favorable outcomes (junior students using Company B) divided by the total number of outcomes (total students). So the probability is $\frac{43}{353}$. Wait, no, wait. Wait, the total number of students is 353? Wait, no, looking at the table again: the "Total" column at the bottom is 103 (Company A) + 110 (Company B) + 140 (Company C) = 353. And the number of junior students using Company B is 43 (from the "Junior" row and "Company B" column). Wait, but the option D is $\frac{43}{353}$? Wait, no, the options: A is $\frac{41}{153}$, B is $\frac{101}{353}$, C is $\frac{110}{353}$, D is $\frac{43}{353}$, E is $\frac{43}{110}$. Wait, no, I think I made a mistake. Wait, the total number of students is 353 (sum of 103, 110, 140). The number of junior students using Company B is 43. So the probability is $\frac{43}{353}$, which is option D. Wait, but let me check again. The "Total" row for all students is 77 (Freshman) + 85 (Sophomore) + 101 (Junior) + 90 (Senior) = 353. And the number of junior students using Company B is 43 (from the "Junior" row and "Company B" column: 24 (A) + 43 (B) + 34 (C) = 101, which matches the "Total" for Junior row: 101). So the number of junior students using Company B is 43, total students is 353. So probability is $\frac{43}{353}$, which is option D.

Answer:

D. $\frac{43}{353}$