QUESTION IMAGE
Question
rebecca surveyed the students at her school to find out which cellphone company they use. her results are listed in the table.
| company a | company b | company c | total | |
|---|---|---|---|---|
| sophomore | 34 | 15 | 36 | 85 |
| junior | 24 | 43 | 34 | 101 |
| senior | 18 | 42 | 30 | 90 |
| total | 103 | 110 | 140 | 353 |
what is the probability that a randomly chosen student is a junior who uses company b?
a. \\(\frac{43}{353}\\)
b. \\(\frac{101}{353}\\)
c. \\(\frac{110}{353}\\)
d. \\(\frac{43}{101}\\)
e. \\(\frac{43}{110}\\)
Step1: Identify the number of junior students using Company B
From the table, the number of junior students using Company B is 43.
Step2: Identify the total number of students
The total number of students surveyed is 353 (from the "Total" row and "Total" column).
Step3: Calculate the probability
The probability is the number of favorable outcomes (junior students using Company B) divided by the total number of outcomes (total students). So the probability is $\frac{43}{353}$. Wait, no, wait. Wait, the total number of students is 353? Wait, no, looking at the table again: the "Total" column at the bottom is 103 (Company A) + 110 (Company B) + 140 (Company C) = 353. And the number of junior students using Company B is 43 (from the "Junior" row and "Company B" column). Wait, but the option D is $\frac{43}{353}$? Wait, no, the options: A is $\frac{41}{153}$, B is $\frac{101}{353}$, C is $\frac{110}{353}$, D is $\frac{43}{353}$, E is $\frac{43}{110}$. Wait, no, I think I made a mistake. Wait, the total number of students is 353 (sum of 103, 110, 140). The number of junior students using Company B is 43. So the probability is $\frac{43}{353}$, which is option D. Wait, but let me check again. The "Total" row for all students is 77 (Freshman) + 85 (Sophomore) + 101 (Junior) + 90 (Senior) = 353. And the number of junior students using Company B is 43 (from the "Junior" row and "Company B" column: 24 (A) + 43 (B) + 34 (C) = 101, which matches the "Total" for Junior row: 101). So the number of junior students using Company B is 43, total students is 353. So probability is $\frac{43}{353}$, which is option D.
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D. $\frac{43}{353}$