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in a random selection of 100 colored candies, 22% of them are blue. the…

Question

in a random selection of 100 colored candies, 22% of them are blue. the candy company claim of blue candies is equal to 23%. use a 0.10 significance level to test that claim.wo decimal places as needed.)p - value for this hypothesis test.e for this hypothesis test is 0.810. three decimal places as needed.)e conclusion for this hypothesis test.ject ( h_0 ). there is sufficient evidence to warrant rejection of the claim that the percentage of blue candies ual to 23%ail to reject ( h_0 ). there is sufficient evidence to warrant rejection of the claim that the percentage of blue andies is equal to 23%ail to reject ( h_0 ). there is not sufficient evidence to warrant rejection of the claim that the percentage of blue andies is equal to 23%reject ( h_0 ). there is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies s equal to 23%

Explanation:

Step1: Hypothesis testing rule

If \(P - value\geq\alpha\) (\(\alpha = 0.10\) here), we fail to reject \(H_0\). If \(P - value<\alpha\), we reject \(H_0\).

Step2: Compare P - value and significance level

Given \(P - value=0.810\) and \(\alpha = 0.10\). Since \(0.810>0.10\) (i.e., \(P - value\geq\alpha\)).

Answer:

Fail to reject \(H_0\). There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to \(23\%\)