Question

question
on a standardized exam, the scores are normally distributed with a mean of 36 and a standard deviation of 5. find the z - score of a person who scored 39 on the exam.
answer attempt 1 out of 2
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Explanation:

Step1: Recall z - score formula

The formula for the z - score is $z=\frac{x-\mu}{\sigma}$, where $x$ is the raw score, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Identify values

We are given that $x = 39$, $\mu=36$, and $\sigma = 5$.

Step3: Substitute values into formula

Substitute the values into the formula: $z=\frac{39 - 36}{5}$.
First, calculate the numerator: $39-36 = 3$.
Then, divide by the standard deviation: $z=\frac{3}{5}=0.6$.

Answer:

0.6