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Question
question 3/5
for the right triangle, △pqr, shown above, what is cos p?
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Step1: Recall the cosine formula in a right - triangle
In a right - triangle, \(\cos\theta=\frac{\text{adjacent side}}{\text{hypotenuse}}\). For angle \(P\), the adjacent side to angle \(P\) is \(r\), and the hypotenuse is \(q\).
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A. \(\frac{r}{q}\)