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question 3/5 for the right triangle, △pqr, shown above, what is cos p? …

Question

question 3/5
for the right triangle, △pqr, shown above, what is cos p?
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Explanation:

Step1: Recall the cosine formula in a right - triangle

In a right - triangle, \(\cos\theta=\frac{\text{adjacent side}}{\text{hypotenuse}}\). For angle \(P\), the adjacent side to angle \(P\) is \(r\), and the hypotenuse is \(q\).

Answer:

A. \(\frac{r}{q}\)