Question

question 1
1 pts

two objects with masses of 0.43 kg and 0.62 kg approach each other with equal momenta of 9.9 kg\frac{m}{s}. find the internal kinetic energy in joules of this system as they approach each other. provide at least one decimal place

Explanation:

Step1: Calculate kinetic energy for first object

The formula for kinetic energy \(K = \frac{p^{2}}{2m}\). For the first object with \(m_1 = 0.43\space kg\) and \(p = 9.9\space kg\cdot m/s\), \(K_1=\frac{(9.9)^{2}}{2\times0.43}\).

$$K_1=\frac{98.01}{0.86}\approx113.965$$

Step2: Calculate kinetic energy for second object

For the second object with \(m_2 = 0.62\space kg\) and \(p = 9.9\space kg\cdot m/s\), \(K_2=\frac{(9.9)^{2}}{2\times0.62}\).

$$K_2=\frac{98.01}{1.24}\approx79.04$$

Step3: Calculate total internal kinetic energy

Since the objects are approaching each other, the total internal kinetic energy \(K = K_1+K_2\).

$$K=113.965 + 79.04=193.005\approx193.0$$

Answer:

\(193.0\)